Write "Java" Program to print below Alphabet Pattern21 (or) Character Pattern21:
To understand this example, you should have knowledge of the following topics:
· Java if Else Statement.
Java Character pattern 21 program using For loop:
import java.util.Scanner;
class alphabetPattern21
{
public static void main(String[] ags)
{
int i, j,k;
System.out.println("Enter the number of lines");
Scanner s = new Scanner(System.in);
k = s.nextInt();
for(i = 1;i <= k;i++)
{
for(j = 1;j <= k-i;j++)
{
System.out.print(" ");
}
for( j = 1; j <= i; j++)
{
System.out.print((char)(j+64));
}
for( j = i -1; j >= 1; j--)
{
System.out.print((char)(j+64));
}
System.out.println();
}
}
}
Output:
Enter the number of lines 5
A
ABA
ABCBA
ABCDCBA
ABCDEDCBA
Explanation:
- The first three integers "i", "j", "k" are declared of type int.
- Then in the First for loop “i” value is initialized with a value of "1".
- Now “i” value is checked with the condition "i <= k" (where the "k" value is given through Keyboard). If the condition is True loops enter into second for loop.
- Now the loop enters into the second for loop and checks the condition "j <= k-i". Where "j = 1". and the condition is True prints the statement.
- Now the loop enters into third for loop and checks the condition "j <= i". If the condition is True print the statement.
- Now the loop enters into the fourth for loop and checks the condition "j >= 1". If the condition is True print the statement.
- Now prints the " Alphabet". Print up to third for loop condition becomes False.
- When the value of "k" becomes less than the "i" value the program terminates.