Alphabet Pattern 10 (or) Character Pattern 10 Program in C

Write "C"  Program to print below Alphabet Pattern 10 (or) Character Pattern 10:

To understand this example, you should have knowledge of the following topics:
·     C if Else Statement
·     C For loop
·     C programming operators
C Character pattern10 program using For loop:
#include<stdio.h>
void main() { int i,j,k = 0 ,m = 1,n; printf("Enter the number of lines\n"); scanf("%d",&n); for(i = 1;i <= n;i++) {
        for(j = 1;j <= i;j++,k++,m++)
        {
          if( k % 2 == 0)
           {
           printf("%c",(char)(m+96));
           }
           else
           {
           printf("%c",(char)(m+64));
            }
        }
        printf("\n");
    }
}


Output:
Enter the number of lines 5
a
Bc
DeF
gHiJ
kLmNo
Explanation:
  • First five integers "i", "j", "k","n","m"  are declared of type int.
  • Then in the First for loop “i” value is initialized with a value of "1". 
  • Now “i” value is checked with the condition "i <= n" (where the "n" value is given through Keyboard). If the condition is True loops enter into second for loop.
  • Now the loop enters into the second for loop and checks the condition j <=i. Where "j = 1". and the condition is True.
  • Now condition enters into if the condition is "True" prints the Printf statement If the condition is "False" Prints the else statement.
  • Now prints the " Alphabet". Print up to second for loop condition becomes False.
  • When the value of "i"  becomes greater than the "n" value the program terminates.
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