Alphabet Pattern 8 (or) Character Pattern 8 Program in C

Write "C"  Program to print below Alphabet Pattern 8 (or) Character Pattern 8:

To understand this example, you should have knowledge of the following topics:

·     C if Else Statement

·     C For loop

·     C programming operators

C Character pattern8 program using For loop:

#include<stdio.h> 
void main()
{
    int i,j,k = 1, n;
    printf("Enter the number of lines\n");
    scanf("%d",&n);
    for(i = 1;i <= n;i++)
    {

        for(j = 1;j <= i;j++,k++)
        {
            printf("%c",(char)(k+64));
        }
        printf("\n");
    }
}

Output:

Enter the number of lines
5

A

BC

DEF

GHIJ

KLMNO

Explanation:

• First four integers "i", "j", "k", "n"  are declared of type int.
• Then in the First for loop “i” value is initialized with a value of "1". 
• Now “i” value is checked with the condition "i <= n" (where the "n" value is given through Keyboard). If the condition is True loops enter into second for loop.
• Now the loop enters into the second for loop and checks the condition j <=i. Where "j = 1". and the condition is True.
• Now prints the " Alphabet". Print up to second for loop condition becomes False.
• When the value of "i"  becomes greater than the "n" value the program terminates.

See also: Alphabet Pattern 7 in C Alphabet Pattern 9 in C

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