Alphabet Pattern 19 (or) Character Pattern 19 Program in C

Write "C"  Program to print below Alphabet Pattern 19 (or) Character Pattern 19:

To understand this example, you should have knowledge of the following topics:

·     C if Else Statement

·     C For loop

·     C programming operators

C Character pattern19 program using For loop:

#include<stdio.h> 
void main()
{
    int i,j,k,n;
    printf("Enter the number of lines\n");
    scanf("%d",&k);
    for(i = 1;i <= k;i++)
    {

         for(j = 1;j <= k-i;j++)
        {

           printf(" ");

        }

         for(n = 1;n <= i;n++)
        {
           printf("%c",(char)(i+64));
        }
printf("\n");
    }
}

Output:

Enter the number of lines
5

       A

      BB

   CCC

 DDDD

EEEEE

Explanation:

• First four integers "i", "j", "k","n" are declared of type int.
• Then in the First for loop “i” value is initialized with a value of "1". 
• Now “i” value is checked with the condition "i <= k" (where the "k" value is given through Keyboard). If the condition is True loops enter into second for loop.
• Now the loop enters into the second for loop and checks the condition "j <= k-i". Where "j = 1". and the condition is True prints the statement.
• Now the loop enters into third for loop and checks the condition "j <= i". Where "n = 1". and the condition is True prints the statement.
• Now prints the " Alphabet". Print up to third for loop condition becomes False.
• When the value of "k"  becomes less than the "i" value the program terminates.

See also: Alphabet Pattern 20 Program in C Alphabet Pattern 18 Program in C

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