C Number pattern 4 program with Explanation ~ Tutorialsweb

Write "C" program to print below Number pattern 4:

To understand this example, you should have knowledge of the following topics:

· C For loop

· C programming operators

C Number pattern 4 program using For loop:

#include <stdio.h>

int main()

{

int i, j;

for(i =1;i<=5;i++)

{

for(j=5;j>=i;j--)

{

printf("%d",j);

}

printf("\n");

}

return 0;

}

Output:

Explanation:

The first two integers "i" and "j" are declared of type int.
Then in the First for loop “i” value is initialized with a value 1.
Now “i” value is checked with the condition i <= 5 that is (1<>= 5). So the condition is True.
Now the loop enters into the second for loop and checks the condition j >= i.
So the value of j=5 is greater than “1” where (j =5) the condition is true. So it's print the value of “J”. And the value of “j” decrements after printing value. It prints the value of J up to “j = 1” when becomes 0 it comes out the loop and increment value i = 2 and the same process repeats.
Last where the “i” value becomes “6” the first for loop condition becomes false and the program terminates.

See also: