Write "C" program to print below Number pattern 1:
To
understand this example, you should have the knowledge of the following topics:
· C programming operators
C Number pattern program using For loop:
#include <stdio.h>
int main()
{
int i, j;
for(i = 5; i >=
1; i--)
{
for(j = 1; j
<= i ;j++)
{
printf("%d",j);
}
printf("\n");
}
return 0;
}
Output:
12345
1234
123
12
1
Explanation:
- The first two integers "i" and "j" are declared of type int.
- Then in the First for loop “i” value is initialized with value 5.
- Now “i” value is checked with the condition i >= 1 that is (5 >=1). So the condition is True.
- Now the loop enters into the second for loop and checks the condition j <= i.
- So the value of j=1 is less than “i” where (i =5) the condition is true. So it's print the value of “J”. And the value of “j” increments after printing value. It prints the value of J up to “j = 5” when becomes 6 it comes out the loop and increment value i = 2 and same process repeats.
- Last where the “i” value becomes “0” the first for loop condition becomes false and the program terminates.
See Also: C Number pattern 2 program