C Number pattern 20 program with Explanation

Write "C"  program to print below Number pattern 20:

To understand this example, you should have knowledge of the following topics:

·     C if Else

·     C For loop

·     C programming operators

C Number pattern 20 program using For loop:

#include<stdio.h>
int main()
{
  int i,j;
  for(i=1;i<=5;i++)
  {
    for(j=1;j<=i;j++)
    {
      printf("%d",j%2);
    }
    printf("\n");
  }
  return 0;
}

Output:

1

10

101

1010

10101

Explanation:

• The first two integers "i", "j" are declared of type int.
• Then in the First for loop “i” value is initialized with a value 1.
• Now “i” value is checked with the condition i < 5 that is (1 < 5). So the condition is True.
• Now the loop enters into the second for loop and checks the condition j <= i. Where "j = 1". and the condition is True.
• Now prints the " j%2" value. Print up to second for loop condition becomes False.
• when the value of "i"  becomes "6" the program terminates.

See also: C Number pattern 19 program C Number pattern 18 program

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