C Number pattern 18 program with Explanation

Write "C"  program to print below Number pattern 18:

To understand this example, you should have knowledge of the following topics:

·     C if Else

·     C For loop

·     C programming operators

C Number pattern 18 program using For loop:

#include<stdio.h>
int main()
{
  int i, j, k;
  for(i=5;i>=1;i--)
  {
    k = i;
    for(j=1;j<=5;j++)
    {
      if(k <= 5)
      {
        printf("%d",k);
      }
      else
      {
        printf("5");
      }
      k++;
    }
  printf("\n");
  }
  return 0;
}

Output:

55555

45555

34555

23455

12345

Explanation:

• The first three integers "i", "j" and "k" are declared of type int.
• Then in the First for loop “i” value is initialized with a value 5.
• Now “i” value is checked with the condition i >= 1 that is (5 >= 1). So the condition is True.
• Now the loop enters into the second for loop and checks the condition j <= 5. Where "j = 1". and the condition is True.
• Now Loop checks if condition "k <=5"  where "k = 5" if the condition is True prints the k value if the Condition is False prints "5". Print up to second for loop condition becomes False.
• when the value of "i"  becomes "0" the program terminates.

See also: C Number pattern 17 program C Number pattern 19 program

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