C Number pattern 14 program with Explanation

Write "C"  program to print below Number pattern 14:

To understand this example, you should have knowledge of the following topics:

·     C if Else

·     C For loop

·     C programming operators

C Number pattern 14 program using For loop:

#include <stdio.h>
int main()
{
  int i,j;
  for(i=7;i >=1;i-=2)
  {
    for(j=1;j<=i;j++)
    {
      printf("%d",j);
    }
    printf("\n");
  }
  return 0;
}

Output:

1234567

12345

123

1

Explanation:

• The first two integers "i", and "j" are declared of type int.
• Then in the First for loop “i” value is initialized with a value 7.
• Now “i” value is checked with the condition i >= 1 that is (7 >= 1). So the condition is True.
• Now the loop enters into the second for loop and checks the condition j <= i. Where "j = 1". and print the value of "j".
• The value of "j" prints up to condition becomes False.
• Now the value of "i" will be decremented by the condition "i = i - 2" and executes the loop.
• when the value of "i"  becomes "0" the program terminates.

See also::C Number pattern 13 program C Number pattern 15 program

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