C Number pattern 16 program with Explanation

Write "C"  program to print below Number pattern 16:

To understand this example, you should have knowledge of the following topics:

·     C if Else

·    C For loop

·    C programming operators

C Number pattern 16 program using For loop:

#include <stdio.h>
int main()
{
  int i,j;
  for(i=1;i<=9;i+=2)
  {
    for(j=i;j<=9;j+=2)
    {
      printf("%d",j);
    }
    printf("\n");
  }
  return 0;
}

Output:

13579

3579

579

79

9

Explanation:

• The first two integers "i", and "j" are declared of type int.
• Then in the First for loop “i” value is initialized with a value 9.
• Now “i” value is checked with the condition i <= 9 that is (1 <= 9). So the condition is True.
• Now the loop enters into the second for loop and checks the condition j <= 9. Where "j = 1". and the condition is True print the value of "j".
• The value of "j" prints up to condition becomes False.
• Now the value of "i" will be incremented by the condition "i = i+2" and executes the loop.
• when the value of "i"  becomes "11" the program terminates.

See also: C Number pattern 15 program C Number pattern 17 program

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