C Number pattern 8 program with Explanation

Write "C"  program to print below Number pattern 8:

To understand this example, you should have knowledge of the following topics:

·     C if Else Statement

·     C For loop

·      C programming operators

C Number pattern 8 program using For loop:

#include <stdio.h>
int main()
{
    int i, j;
    for(i=5;i>=1;i--)
    {
        for(j=5;j>=i;j--)
        {
            printf("%d",j);
        }
        printf("\n");
    }
    return 0;
}

Output:

5

54

543

5432

54321

Explanation:

• The first two integers "i" and "j" are declared of type int.
• Then in the First for loop “i” value is initialized with a value "5".
• Now “i” value is checked with the condition i >= 1 that is (5 >= 1). So the condition is True.
• Now the loop enters into second for loop and checks the condition j >= i. Where "j = 5".
• So the value of j=5 is equal to the value of "i" it prints the value if "j". Now the value of "j" is decremented to "4" the second for loop condition becomes false loop come out from them for a loop.
• Now the value of "i" is decremented to "4" and repeat the same process.
• Last where the “i” value becomes “0” the first loop condition becomes false and the program terminates.

See Also: C Number pattern 7 program C Number pattern 9 program

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