C Number pattern 19 program with Explanation

Write "C"  program to print below Number pattern 19:

To understand this example, you should have knowledge of the following topics:

·     C if Else

·     C For loop

·     C programming operators

C Number pattern 19 program using For loop:

#include<stdio.h>
int main()
{
  int i,j,k;
  k=1;
  for(i=1;i<5;i++)
  {
    for(j=1;j<=i;j++)
    {
      printf("%d",k++);
    }
    printf("\n");
  }
  return 0;
}

Output:

1

23

456

78910

Explanation:

• The first three integers "i", "j" and "k" are declared of type int.
• Then in the First for loop “i” value is initialized with a value 1.
• Now “i” value is checked with the condition i < 5 that is (1 < 5). So the condition is True.
• Now the loop enters into the second for loop and checks the condition j <= i. Where "j = 1". and the condition is True.
• Now prints the k value by condition "k++". Print up to second for loop condition becomes False.
• when the value of "i"  becomes "6" the program terminates.

See also: C Number pattern 18 program C Number pattern 20 program

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