C Number pattern 17 program with Explanation

Write "C"  program to print below Number pattern 17:

To understand this example, you should have knowledge of the following topics:

·     C if Else

·     C For loop

·     C programming operators

C Number pattern 17 program using For loop:

#include<stdio.h>
int main()
{
  int i,j,k;
  for(i=1;i<=5;i++)
  {
    if(i%2==0) 
    {
      k=2; 
    }
    else 
    {
      k=1;
    }
    for(j=1;j<=i;j++,k+=2)
    {
      printf("%d ", k);
    }
    printf("\n");
  }
  return 0;
}

Output:

1

24

135

2468

13579

Explanation:

• The first two integers "i", and "j" are declared of type int.
• Then in the First for loop “i” value is initialized with a value 5.
• Now “i” value is checked with the condition i <= 5 that is (1 <= 5). So the condition is True.
• Now Loop check if condition "i % 2" if the condition is True k value becomes "2" if the condition is false K value becomes "1"
• Now the loop enters into the second for loop and checks the condition j <= i. Where "j = 1". and the condition is True print the value of "k".
• The value of "j" prints up to condition becomes False.
• Now the value of "i" will be incremented by the condition "i = i++" and executes the loop.
• when the value of "i"  becomes "6" the program terminates.

See also: C Number pattern 16 program C Number pattern 18 program

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