Alphabet Pattern 20 (or) Character Pattern 20 Program in Java ~ Tutorialsweb

Write "Java" Program to print below Alphabet Pattern20 (or) Character Pattern20:

To understand this example, you should have knowledge of the following topics:

· Java if Else Statement.

· Java For loop
· Java programming operators.

Java Character pattern 20 program using For loop:

import java.util.Scanner;

class alphabetPattern20

public static void main(String[] ags)

    int i, j,k;

   System.out.println("Enter the number of lines");

   Scanner s = new Scanner(System.in);

   k = s.nextInt();

    for(i = 1;i <= k;i++)

        for(j = 1;j <= k-i;j++)

            System.out.print(" ");

           for( j = i; j > 0; j--)

            System.out.print((char)(j+64));

          for( j = 2; j <= i; j++)

            System.out.print((char)(j+64));

        System.out.println();

Output:


Enter the number of lines
5

       A

     BAB

   CBABC

 DCBABCD

EDCBABCDE

Explanation:

The first three integers "i", "j", "k" are declared of type int.
Then in the First for loop “i” value is initialized with a value of "1".
Now “i” value is checked with the condition "i <= k" (where "k" value is given through Keyboard). If the condition is True loops enter into second for loop.
Now the loop enters into the second for loop and checks the condition "j <= k-i". Where "j = 1". and the condition is True prints the statement.
Now the loop enters into third for loop and checks the condition "j > 0". If the condition is True prints the statement.
Now the loop enters into the fourth for loop and checks the condition "j <= i". If the condition is True prints the statement.
Now prints the " Alphabet". Print up to third for loop condition becomes False.
When the value of "k" becomes less than "i" value the program terminates.

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